.......... back at it.....
OK, now that the circle is on there, I punch a bunch of center punch marks for the drill to ride in.
Using a fairly small bit, maybe 1/8", I drill a series of holes around the circle.
It does not seem to matter how much time you take, you always seem to have a few times when the drill bit does not want to go straight down, but wants to wonder sideways...........
.........when this happens, flip the thing over and start another hole on the back side.
Something else I do, is put a catch pan of sorts under the drill press table, to catch the pieces of metal, it does not get them all, but it it might at the very least keep the clean up down.
OK, my holes are drilled, so now I clamp the pieces in the vice, and get out my Jigsaw with the metal cutting blade on it............
.....and in no time at all, I have two holes in the saddle pieces!
I put a round grinding stone that can be chucked up in Kermit to make the inside edge somewhat smooth (forgot to take pics of it
) and I also ground the bearing holder a bit, as I needed to remove the paint etc if I am going to weld it.
here are some pics of the round idea.
The thing is, the shaft will have to be straight and level in this, so what I'm going to do is to re-install the old bearings into the bearing holder, with the shaft in there too, then I'll check for level and square and weld away, once done, I'll take the old bearings out (as they will get cooked in the welding process, just from the near by heat, and replace them with the new bearings. Yes, I'm going to weld the cast iron bearing holder to the bearing saddle, I'll use my Mig, it worked well enough on Kermit's table...?
I'm actually waiting to weld up the frame on finishing the bearing saddle, as I need to know the clearance I need for the bearing saddle under the bottom section of the frame.
Well, what do you think?
BTW, can some one check my math for me?
Blade length = 267 cm (105")
Wheel Diameter = 35 cm
Wheel Circumference = 110 cm
Now, at anytime, the blade is only touching half of each wheel, so the circumference of the blade, minus the circumference of one wheel
(the top half of the top wheel, and the bottom half of the bottom wheel) which is 157 cm
267 - 110 = 157
This is the length of the straight portions of the blade, of which there are two, the front and the back side of the blade.
Divide 157 cm by 2 and you get 78.5 cm, which would be the distance between the center of the two wheels........... right?
Hope so......
Cheers!